What Is the Full Denominator of the GK-22 Deliverability Equation?
The pseudo-steady-state gas deliverability equation assembled in SP-5 has the form:
From SP-3 you have keff = 35.7 mD and h = 94 ft. From SP-2 you have μg = 0.0312 cp, Z = 1.40, T = 745°R. What remains is the complete geometric denominator Gtotal. For a vertical oil well, G = ln(re/rw) − ¾ + S. For GK-22, a high-rate gas well, there is an additional rate-dependent term: the non-Darcy (Forchheimer) turbulence skin S′ = D·qg.
Your tasks in SP-4 are:
- Compute ln(re/rw) for the 640-acre drainage and 9⅝" wellbore.
- Assemble Gbasic = ln(re/rw) − ¾ + S with provisional skin S = +2.5.
- Compute the non-Darcy skin S′ = D·q at the DST rate q = 12,400 Mscfd with D = 0.00035 d/Mscf.
- Assemble Gtotal = Gbasic + D·q and break it into its four components.
- Evaluate two engineering options, stimulation (remove S) versus rate restriction (reduce D·q), and quantify which yields greater PI improvement.
- Assess the sensitivity of Gbasic to a 30% change in re to demonstrate the logarithm's damping effect.
Data Relevant to This Sub-Problem
| Parameter | Symbol | Value | Units | Relevance to SP-4 |
|---|---|---|---|---|
| Drainage radius | re | 2,980 | ft | Primary geometric input for ln(re/rw) |
| Wellbore radius | rw | 0.354 | ft | 9⅝" casing ID ÷ 24 in/ft → rw in ft |
| Mechanical skin (DST provisional) | S | +2.5 | — | Positive skin = near-wellbore damage; adds to denominator |
| Non-Darcy coefficient | D | 0.00035 | d/Mscf | Turbulence coefficient: compute D·q at each rate of interest |
| DST stabilised gas rate | qg,DST | 12,400 | Mscfd | Calculate D·q at DST rate for initial Gtotal |
| Gas viscosity | μg | 0.0312 | cp | From SP-2, used in SP-5 deliverability equation |
Key Concepts for SP-4: Drainage Geometry and Non-Darcy Flow
Full treatment in Topic 1.4: Drainage Geometry.
Pseudo-Steady-State Geometric Factor: Derivation
For a vertical well centred in a circular drainage area under pseudo-steady-state flow, Darcy's radial flow equation integrates to give a denominator:
Non-Darcy Flow: Forchheimer Extension to Darcy's Law
Darcy's law assumes linear (laminar, viscous-dominated) flow: dP/dr = μq/(kA). At high gas velocities near the wellbore of a high-rate gas well, inertial forces become significant — the Forchheimer equation adds a velocity-squared (quadratic) term:
Component Decomposition of Gtotal: What Drives the Denominator?
| Component | GK-22 Value | Fraction of Gtotal | Sensitivity | Engineering lever |
|---|---|---|---|---|
| ln(re/rw) | 9.038 | ~60% | LOW: logarithm dampens re uncertainty | Larger wellbore (rw) reduces G slightly; diminishing returns |
| −¾ (PSS correction) | −0.750 | — | Fixed for PSS circular drainage | None, fixed geometry term |
| Mechanical skin S | +2.500 | ~16% | HIGH: each unit S changes G by ~1/G × 100% | Acid stimulation, perforation optimisation |
| Non-Darcy D·q | +4.340 (at DST rate) | ~29% | HIGH and rate-dependent: D·q increases with q | Rate management, larger perforated interval, horizontal well |
SP-4 Tasks: Work Through in Order
- Task 4.1: Calculate ln(re/rw)
Compute re/rw = 2,980/0.354. Then calculate the natural logarithm (ln, base e, not log10). Express to three decimal places. Confirm by checking: ln(8,000) ≈ 8.99, so your answer for a ratio of ~8,418 should be close to 9.04. State clearly: this is the natural log (ln), not the common log (log10), getting this wrong by a factor of 2.303 is the most common calculation error in radial flow equations. - Task 4.2: Assemble Gbasic
Add the three components: Gbasic = ln(re/rw) − 0.750 + S. With S = +2.5 and your ln result from Task 4.1: compute Gbasic to three decimal places. Calculate the percentage of Gbasic contributed by the skin term alone (S/Gbasic × 100%). This tells you how much PI improvement is available from stimulation that removes the skin. - Task 4.3: Compute Non-Darcy Apparent Skin at DST Rate
Using D = 0.00035 d/Mscf and qg = 12,400 Mscfd (= 12.4 MMscfd expressed in Mscfd): calculate S′ = D × qg. Show units explicitly (d/Mscf × Mscfd = Mscf/Mscf × Mscf/d × d/Mscf, simplify to dimensionless). Compare S′ to mechanical skin S = 2.5. Which dominates? By what factor? State the physical interpretation: what does S′ = 4.34 mean for the well's ability to produce at the DST rate? - Task 4.4: Assemble Gtotal and Decompose
Compute Gtotal = Gbasic + D·q. Compare to Gbasic. Calculate the percentage by which non-Darcy turbulence increases the geometric denominator (and therefore reduces AOF) at the DST rate. Present a four-row decomposition table: component name, value, and percentage of Gtotal. - Task 4.5: Stimulation vs. Rate Management: Quantify the PI Benefit
Evaluate two options, each starting from Gtotal = 15.13 at 12.4 MMscfd:
Option A — Acid stimulation removes mechanical skin (S: +2.5 → 0); D·q unchanged at 4.34. Calculate new Gtotal,A and PI improvement (PI ∝ 1/G).
Option B: Rate restriction to qg = 8,000 Mscfd; S unchanged at +2.5. Recalculate D·q and new Gtotal,B. Calculate the PI improvement (note: rate restriction also directly reduces production revenue — consider this in your assessment).
State which option provides superior PI improvement per unit engineering effort. Is this result surprising? What does it imply about the value of stimulation for this well? - Task 4.6, re Sensitivity: How Much Does Drainage Area Uncertainty Matter?
If the actual effective drainage radius is 2,100 ft (a 30% reduction from the assumed 2,980 ft, possible if adjacent wells drain overlapping areas), recalculate Gbasic with re = 2,100 ft. Compare to the original Gbasic. Calculate the percentage change in Gbasic. What does this tell you about the sensitivity of AOF to well spacing assumptions? Compare this sensitivity to a ±1 unit change in skin S.
SP-4 Worked Answers
Tasks 4.1–4.4: Gtotal Full Assembly
Task 4.5: Stimulation vs. Rate Management
Task 4.6: re Sensitivity
GK-22 at 12.4 MMscfd has D·q = 4.34: the turbulence skin exceeds the mechanical skin by 74%. For a horizontal well with 800 ft of open hole (effective rw,effective enlarged dramatically), the near-wellbore velocity would be far lower and D would be smaller. Discuss: if GK-22 had been drilled as a horizontal well, how would the denominator change? Which of the four components (ln term, PSS correction, S, D·q) would be most affected and in which direction?
Update Your KWL Table: SP-4
- Gbasic = ln(re/rw) − ¾ + S for PSS circular drainage
- Must use ln (natural log), NOT log10
- Skin adds directly to G, units cancelled to dimensionless
- re uncertainty is damped by the logarithm
- D·q = 4.34 at DST rate: 74% larger than mechanical skin S = 2.5
- Gtotal = 15.13; ignoring D·q overstates AOF by 40%
- Stimulation (+19.8% PI) beats rate restriction (+11.3%)
- 30% re change → only 3.2% change in G
- ±1 skin unit → ±8–9% AOF, 3× more impact than re uncertainty
- Write your own entry
- Example: "D·q is rate-dependent — the deliverability equation is nonlinear in q for gas wells; iterating to find true AOF requires solving Gtotal(q) = f(q)"
Just-in-Time Resources
Reach for these the moment you get stuck on this sub-problem. They map one-to-one onto the physics and the calculation you are doing here.
- Lecture 1.4A — Geometry Matters: How Boundary Shape Controls Deliverability
- Lecture 1.4B — Radial Flow to Steady-State IPR: Step by Step
geometry_calculator.py, verified calculator; reproduce your numbers.
SP-4: Five MCQ
Q1: ln(re/rw) Calculation
For GK-22 with re = 2,980 ft and rw = 0.354 ft, the correct value of ln(re/rw) is:
Explanation
Q2: What the −¾ Term Represents
In the geometric factor G = ln(re/rw) − ¾ + S, the −¾ correction:
Explanation
Q3: Non-Darcy Apparent Skin S′
At qg = 12,400 Mscfd with D = 0.00035 d/Mscf, the non-Darcy apparent skin S′ is:
Explanation
Q4: Gtotal and AOF Penalty
Gtotal for GK-22 at the DST rate of 12.4 MMscfd is:
Explanation
Q5: re Sensitivity via Logarithm Damping
If re is reduced from 2,980 to 2,100 ft (a 30% reduction), Gbasic changes by approximately:
Explanation
Carry-Forward to SP-5
SP-4 Carry-Forward Values: Record These Now
CF-4a, ln(re/rw): 9.038 (natural log of 8,418; re/rw = 2,980/0.354)
CF-4b — Gbasic: 10.788 (= 9.038 − 0.750 + 2.500)
CF-4c — Non-Darcy skin at DST rate: S′ = D·q = 0.00035 × 12,400 = 4.340
CF-4d — Gtotal at DST rate (12.4 MMscfd): 15.128 ≈ 15.13
CF-4e — D·q at AOF rate (for SP-5 iteration): recalculate D·q when AOF is known; AOF will be higher than 12.4 MMscfd so Gtotal at AOF > 15.13
CF-4f — Stimulation benefit: removing S reduces Gtotal from 15.13 → 12.63 (+19.8% PI improvement)
CF-4g, re sensitivity note: 30% re change → only 3% AOF change; skin dominates PI sensitivity